Comments on: A person wears a hearing aid, which makes a sounds louder by 10 dB?

By: apbupemcje

apbupemcje — Sun, 05 Jul 2009 08:41:42 +0000

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Louloute Ministre Désinformation — Fri, 03 Jul 2009 20:24:52 +0000

10db = 10 log(Po/Pi)

Log (Po/Pi) = 10/10 = 1

Po/Pi = 10 power 1

Po/Pi = 10

Po = 10 Pi

10db = 20 log (Uo/Ui)

Log (Uo/Ui) = 0.5

Uo/Ui = 10 power 0.5 = 3.16

Uo = 3.16 Ui

islandgrl — Fri, 03 Jul 2009 10:40:02 +0000

I= 10^ (10/10) = 10 times
A = sqrt(ans above) = sqrt(10) = 3.16

Andy M — Wed, 01 Jul 2009 05:54:43 +0000

10 dB = 10^10 = 10,000,000,000

This means the sound intensity is increased …..10^10…… times.
This means the amplitude of the soundwave is increased ……..10^10…….times.

I don’t know much about hearing loss, but based on the numbers, this person seems to be quite deaf!

jadedheart — Mon, 29 Jun 2009 07:08:01 +0000

increased by 10 db